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Archived from groups: rec.audio.high-end (More info?)
Sean Fulop <sfulop@uchicago.edu> wrote:
> And I repeat, we cannot be sure that everything can be measured. No
> researcher in sound or signal processing could be taken seriously if he
> said otherwise, given the advances in measuring properties of the signal
> that are made each week and reported in the journals. Now, on the other
> hand, if two outputs produce exactly the same signal down to the 96 kHz
> sampled bit, then they are indeed "the same". Comparing two digitized
> signals can be done simply, just look at their matrices and see whether
> the cells all have the same numbers.
> But I don't think this is what people mean when they say there is "no
> measurable difference," they are usually talking about staring at some
> graph or chart or something that has been computed as a property of the
> signals. And there is good reason to try this, since the bit-identity of
> two signal waveforms is really not at all correlated with two signals
> seeming to "sound the same." Drastically different signals can be
> easily made which sound the same, because of the variety of effects to
> which the ear is not sensitive.
Seems to me you have it backwards.
Two bit-identical tracks will very likely sound the same.
Tus bit-identity is correlated to aural identity; more
properly, it is *sufficient* for aural identity.
That does not mean that *sounding the same* correlates as well to
bit-identity. The relationship is not reciprocal, for the
reason you state. Aural identity is not sufficient reason
to conclude bit-identity.
--
-S.
Why don't you just admit that you hate music and leave people alone. --
spiffy <thatsright@excite.co>
Sean Fulop <sfulop@uchicago.edu> wrote:
> And I repeat, we cannot be sure that everything can be measured. No
> researcher in sound or signal processing could be taken seriously if he
> said otherwise, given the advances in measuring properties of the signal
> that are made each week and reported in the journals. Now, on the other
> hand, if two outputs produce exactly the same signal down to the 96 kHz
> sampled bit, then they are indeed "the same". Comparing two digitized
> signals can be done simply, just look at their matrices and see whether
> the cells all have the same numbers.
> But I don't think this is what people mean when they say there is "no
> measurable difference," they are usually talking about staring at some
> graph or chart or something that has been computed as a property of the
> signals. And there is good reason to try this, since the bit-identity of
> two signal waveforms is really not at all correlated with two signals
> seeming to "sound the same." Drastically different signals can be
> easily made which sound the same, because of the variety of effects to
> which the ear is not sensitive.
Seems to me you have it backwards.
Two bit-identical tracks will very likely sound the same.
Tus bit-identity is correlated to aural identity; more
properly, it is *sufficient* for aural identity.
That does not mean that *sounding the same* correlates as well to
bit-identity. The relationship is not reciprocal, for the
reason you state. Aural identity is not sufficient reason
to conclude bit-identity.
--
-S.
Why don't you just admit that you hate music and leave people alone. --
spiffy <thatsright@excite.co>