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Archived from groups: rec.audio.pro (More info?)
"Arny Krueger"
> "Phil Allison"
** Arny is trying to shift the context again - so I had to put it back.
> > If that 100uF cap developed 100 ohms of ESR then the channel's
> > gain drops by 3 dB.
>> Wrong.
** Nope - Arny is *dead wrong* - yet AGAIN !!!!!
> >
> >> As long as there's a few uF capacitance in the capacitor, there's a
> >> turnover point in the frequency response curve. Basic network
> >> analysis. It ain't much of a turnover point, but there will be a
> >> measurable FR change.
>
> >
> > ** ESR is the issue - the "S" in ESR stands for "series ". Any
> > ESR associated with that 100uf cap *adds* to the value of 270 ohm
> > resistor in the feedback network and reduces the amp's gain.
>
>
> Exactly.
** So Arny admits he was wrong.
> So work out the frequency response of the origional network, and
> the new network.
** I already did - it is still flat.
The extra 100 ohms only reduces the gain.
> You'll find that the small capacitance of the partially-failed shunt
> capacitor and it higher ESR can create a frequency-sensitive network.
>
** That is a really desperate attempt to move the context.
There need not be any loss of capacitance with a rise in the ESR.
What a despicable fake you are Arny.
.............. Phil
"Arny Krueger"
> "Phil Allison"
** Arny is trying to shift the context again - so I had to put it back.
> > If that 100uF cap developed 100 ohms of ESR then the channel's
> > gain drops by 3 dB.
>> Wrong.
** Nope - Arny is *dead wrong* - yet AGAIN !!!!!
> >
> >> As long as there's a few uF capacitance in the capacitor, there's a
> >> turnover point in the frequency response curve. Basic network
> >> analysis. It ain't much of a turnover point, but there will be a
> >> measurable FR change.
>
> >
> > ** ESR is the issue - the "S" in ESR stands for "series ". Any
> > ESR associated with that 100uf cap *adds* to the value of 270 ohm
> > resistor in the feedback network and reduces the amp's gain.
>
>
> Exactly.
** So Arny admits he was wrong.
> So work out the frequency response of the origional network, and
> the new network.
** I already did - it is still flat.
The extra 100 ohms only reduces the gain.
> You'll find that the small capacitance of the partially-failed shunt
> capacitor and it higher ESR can create a frequency-sensitive network.
>
** That is a really desperate attempt to move the context.
There need not be any loss of capacitance with a rise in the ESR.
What a despicable fake you are Arny.
.............. Phil