{JAVA} Calculating PI without using class.math

[ECSD]

Is it possible to calculate the Number PI without using the java class math?

I found this formula to calculate PI.

I think i need some int arrays to save the numbers but actually i'm stumped.

Has anyone a hint?

 

[Sunius]

That's not formula to calculate PI.. That's a formula for arcsine.

Shouldn't be that hard

double Pi = 4;
bool plus = 0;
for (int i = 3; i < 10000000; i += 2)
{
    if (plus)
    {
        Pi += 4.0 / i;
    }
    else
    {
        Pi -= 4.0 / i;
    }
    plus = !plus;
 }

 

[ECSD]

Is that C?

 

[Sunius]

Does it matter? It would work on many languages. I tested it using Visual C++ compiler. I'm sure you can convert it to Java without any problems.

 

[ECSD]

I don't know what
"bool plus = 0;" means "

and

"plus = !plus;"

 

[randomizer]

It's a flag which determines whether or not to do an add operation or a subtract operation, and it is flipped* each time either is performed so that the two alternate. For Java you'd have to initialise the boolean to false, not 0.

*The ! inverts the boolean result of whatever follows it. So if "plus" is true, it will return false and vice versa.

 

[ECSD]

Thanks. Should "i" be also a variable?
Because in Java you can't divide i if it is not declared as a variable.

 

[randomizer]

It is already declared and initialised at the start of the for loop, and its scope is restricted to the loop as well.

I'm guessing this task is for some homework. I can't think of any common reason to want to manually calculate pi except because you are told that you must.

 

[Sunius]

I'm not really familiar with Java syntax, but from what randomizer said bool plus = 0 equivalent in Java should be:

boolean plus = false;

And as for i, it's declared in the loop at line 3:

int i = 0;

Finally, operator ! flips the boolean value, if it was true, it becomes false, and if it was false, it becomes true.

 

[Guest]

Hi,

I was given the same task as ECSD, using the arcsine formula from the first post. Further info: when x=0.5 --> 6*arcsin(x) = Pi . That's how the formula might be incorporated. I'm completely new to Programming and I'm confused as to how to calculate to a power without using the Math.Class... I have the instructions to not use the Math.Class and to save the first 10000 digits of Pi in int-arrays.. any advice would be much appreciated

 

[Sunius]

Do you have instructions to what x degree you need to calculate? Like 1000? 10000?

 

[Guest]

no, other than the 10000 digits of Pi there's nothing specifically specified..

 

[Sunius]

I suppose you'll have to write your own operators: +, *, /, which take arrays as operands instead of numbers. That's the only way I see it would work.